1 条题解
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0
C :
#include<stdio.h> int main() { int n,i,a,max,min; scanf("%d",&n); for(i=1; i<=n; i++) { scanf("%d",&a); if(i==1) { max=a; min=a; } if(a>max) { max=a; } if(a<min) { min=a; } } printf("max=%d, min=%d\n",max,min); }C++ :
#include<stdio.h> int main() { int N,a,max,min,i; scanf("%d",&N); for(i=1;i<=N;i++) { scanf("%d",&a); if(i==1) { max=a; max=a; } if(a>max) { max=a; } if(a<min) { min=a; } } printf("max=%d, min=%d",max,min); return 0; }Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int n = sc.nextInt(); int[]a=new int[n]; a[0]=sc.nextInt(); int max = a[0]; int min = a[0]; for (int i = 1; i < n; i++){ a[i]=sc.nextInt(); if (a[i]>max){ max = a[i]; } if (a[i]<min){ min = a[i]; } } System.out.println("max=" + max + ", min=" + min); } }Python :
# coding=utf-8 #python2 str = raw_input() list1 = str.split() #首字符出列 n = int(list1.pop(0)) min = max = int(list1[0]) i = 0 x = n while i<x: m = int(list1.pop()) if max<m: max = m if min>m: min = m i += 1 print("max=%d, min=%d"%(max,min))
- 1
信息
- ID
- 38
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- 3
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者